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Let b1b2b3b4 be a 4-element permutation with bi 
 {1, 2, 3, ..., 100} for 1 
 i ≤ 4 and bi 
 bj for i ≠ j, such that either b1, b2, b3 are consecutive integers or b2, b3, b4 are consecutive integers.

Then the number of such permutations b1b2b3b4 is equal to _________. (in integers)
Correct answer is '18915'. Can you explain this answer?
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Let b1b2b3b4be a 4-element permutation with bi∈{1, 2, 3, ..., 100...
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Let b1b2b3b4be a 4-element permutation with bi∈{1, 2, 3, ..., 100} for 1≤i≤ 4 and bi≠bjfor i≠ j, such that either b1, b2, b3are consecutive integers or b2, b3, b4are consecutive integers.Then the number of such permutations b1b2b3b4is equal to _________. (in integers)Correct answer is '18915'. Can you explain this answer?
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Let b1b2b3b4be a 4-element permutation with bi∈{1, 2, 3, ..., 100} for 1≤i≤ 4 and bi≠bjfor i≠ j, such that either b1, b2, b3are consecutive integers or b2, b3, b4are consecutive integers.Then the number of such permutations b1b2b3b4is equal to _________. (in integers)Correct answer is '18915'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Let b1b2b3b4be a 4-element permutation with bi∈{1, 2, 3, ..., 100} for 1≤i≤ 4 and bi≠bjfor i≠ j, such that either b1, b2, b3are consecutive integers or b2, b3, b4are consecutive integers.Then the number of such permutations b1b2b3b4is equal to _________. (in integers)Correct answer is '18915'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let b1b2b3b4be a 4-element permutation with bi∈{1, 2, 3, ..., 100} for 1≤i≤ 4 and bi≠bjfor i≠ j, such that either b1, b2, b3are consecutive integers or b2, b3, b4are consecutive integers.Then the number of such permutations b1b2b3b4is equal to _________. (in integers)Correct answer is '18915'. Can you explain this answer?.
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